unwilling-turquoise•4y ago

How to create a new cheerio instance $?

I need to instatiate a new cheerio object, i'm doing a search in a set o elements and need to select just one element for further processing, my actual code is:

function getOrigin($: typeof cheerioModule) {
    let origin = ""
    const specElements = $('#product_specs table tr').toArray()
    for (const spec of specElements) {
        const _$ = cheerioModule.load(spec)
        const specTitle = _$(".attrib").text().trim()
        if(specTitle.includes("제조국")){
            origin = _$(".attrib-val").text().trim()
            break
        }
    }
    return origin
}

function getOrigin($: typeof cheerioModule) {
    let origin = ""
    const specElements = $('#product_specs table tr').toArray()
    for (const spec of specElements) {
        const _$ = cheerioModule.load(spec)
        const specTitle = _$(".attrib").text().trim()
        if(specTitle.includes("제조국")){
            origin = _$(".attrib-val").text().trim()
            break
        }
    }
    return origin
}

but i'm not sure if that is the right way to instantiate a new cheeio object in crawlee.

1 Reply

continuing-cyan•4y ago

You don't need to use load(). Instead of doing this:

const _$ = cheerioModule.load(spec);

const _$ = cheerioModule.load(spec);

Just do this using the $ already provided to you by Crawlee:

const elem = $(spec);

const elem = $(spec);

It will return a Cheerio object scoped only to that spec element. 😄

How to create a new cheerio instance $?

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